Question

Given triangle ABC, cos A = sqrt2 /3 find the exact value of side a

Answer 1

Answer:

sqrt7

Step-by-step explanation:

cosA = b/3 = sqrt2 /3

so b = sqrt2

apply the pythagorean theorem

a = sqrt7

Answer 2

Answer: √7

Step-by-step explanation:

cos A = adj / hyp = √2 / 3

We need to find the angle A before we proceed

cos A = 0.4714

A = arccos(0.4714)

A =61.87

adj =√2 hyp = 3 opp =a

sin A = opp / hyp

sin61.87 = a / 3

cross multiply

a = 3 sin 61.87

a = 3 × 0.88188

a =2.6456

a = √7