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djverab [1.8K]
3 years ago
12

5x36=(5x__) + (5x__) 5x36= __+__ 5x36=___

Mathematics
2 answers:
Viktor [21]3 years ago
4 0
Not sure. Sorry.
Is this your homework??
Cloud [144]3 years ago
4 0
5X36=(5X18) + (5X18)
5X36=90+90
5X36=180

That's the real, correct answer
Your welcome
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How do I know when two fractions are equivalent​
vlada-n [284]

Answer:

when they

Step-by-step explanation:

equal the same value when you break them up

3 0
2 years ago
Natalie picked 135 berries in 15 minutes. If she continues picking at that rate, how many total minutes will it take her to pick
Alex777 [14]
Lets focus on what we know first. Natalie can pick 135 Berries in 15 minutes. Lets find out how many berries she can pick per minute.
In order to do so, We have to divide 135 by 15.

135/15=9
This means that Natalie can pick 9 berries per minute. Given that we want her to pick 486, we will need to divide that number by 9 berries to find out how many minutes it will take to get her to that number of berries.

486/9=54

This means that it will take Natalie 54 minutes in order to pick 486 berries. 
5 0
3 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
15 points. What is the value of k?
Lubov Fominskaja [6]

Answer:

k = 10

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ ZYM is an exterior angle of the triangle, thus

4k + 5 + 6k + 10 = 115, that is

10k + 15 = 115 ( subtract 15 from both sides )

10k = 100 ( divide both sides by 10 )

k = 10

7 0
3 years ago
Read 2 more answers
An expression is shown.
Anettt [7]

Answer:

im pretty sure its D :) hope this helps you out.

7 0
2 years ago
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