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3 years ago

F (×)=3×^2-3× g (×)=-5×-1 find f (-4) and g (7)

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

Very simple. All you have to do is replace -4 instead of x for F(x) and for g(x) you replace 7 for the x

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3x+2=11,what does this equal to I’m confused

kicyunya [14]

Answer:

Step-by-step explanation:

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2 years ago

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The average distance from the sun to venus is 67,237,910 miles. The average distance from the sun to earth is 92,955,807 miles.

timofeeve [1]

Both are correct, the earth is about 93 million miles away and Venus is about 67 million miles away from the sun.

4 0

3 years ago

The formula v= u+ atdescribes connections between u: starting velocity a: acceleration t: time v: final velocity a)In a particul

Bess [88]

Answer:

49 = 0 +9.8t
t = 5

Step-by-step explanation:

It usually works to follow directions.

a) Substitute the numbers into the formula:

v = u + at

49 = 0 +9.8t

b) Solve the equation:

49/9.8 = t = 5 . . . . . divide by the coefficient of t

6 0

2 years ago

One student begins in Cleveland, Ohio, and walks towards Buffalo, New York, a distance of 200 miles. She walks at the rate of 2.

omeli [17]

Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t

the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)

A. x=2.5t
y=11(t-4)

when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647

answer is 5.18 hours

A.
x=2.5t
y=11(t-4)

B. 5.18 hours

6 0

2 years ago

a mechanic worked 20 hours. another mechanic worked 15 hours. together they charged a total of $1950. what was the rate charged

Natasha_Volkova [10]

Answer: The mechanics both charged $70 and $45 per hour respectively

Step-by-step explanation: We shall start by calling the mechanics hourly rates x and y respectively. So if one worked for 20 hours and charged 20 times x dollars, and the other one worked for 15 hours and charged 15 times y dollars, totalling 1950 dollars, we can write the following expression,

20x + 15y = 1950

Also, if the sum of the two rates was 115 dollars, that means for working for an hour only, they both would earn

x + y = 115

We now have a pair of simultaneous equations

20x + 15y = 1950 --------(1)

x + y = 115 ------------------(2)

We shall use the substitution method for this problem.

From equation (2), make x the subject of the equation

x = 115 - y

Substitute for the value of x into equation (1)

20(115 - y) + 15y = 1950

2300 - 20y + 15y = 1950

By collecting like terms we now have

2300 - 1950 = 20y - 15y

(Note that when a negative value crosses to the other side of the equation, it becomes a positive value and vice versa)

350 = 5y

Divide both sides of the equation by 5

70 = y

We now substitute for the value of y into equation (2)

x + y = 115

x + 70 = 115

Subtract 70 from both sides of the equation

x = 45.

Therefore, the rate they charged per hour were $45 and $70 respectively.

7 0

3 years ago