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Scrat [10]
2 years ago
14

11 relaxing after work. the 2010 general social survey asked the question: "after an average work day, about how many hours do y

ou have to relax or pursue activities that you enjoy?" to a random sample of 1,155 americans.41 a 95% confidence interval for the mean number of hours spent relaxing or pursuing activities they enjoy was (1.38, 1.92). (a) interpret this interval in context of the d
Mathematics
1 answer:
Bogdan [553]2 years ago
3 0
A confidence interval tells us how many percents we are confident about the range of a parameter. In this problem, <span>a 95% confidence interval for the mean number of hours spent relaxing or pursuing activities they enjoy was (1.38, 1.92). That means we're 95% confident that the Americans spend from 1.38 hours to 1.92 hours per day on average relaxing or pursuing activities they enjoy. In other words, 95% of the samples of the same size would have a mean number of hours relaxing or pursuing activities they enjoy between 1.38 to 1.92.</span>
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What is the mean of the data set? {32, 33, 34, 34, 36, 38, 38, 38, 40, 42}
Sphinxa [80]
Add all the numbers:

32 + 33  34 + 34 + 36 + 38 + 38 + 38 + 40 + 42 = 365

There are 10 numbers.

Divide:
Total by how many numbers there are

Total = 365
Numbers = 10

365 / 10 = 36.5

The mean is 36.5

Hope this helped☺☺


7 0
2 years ago
Read 2 more answers
A 2x2 square is centered on the origin. It is dilated by a factor of 3. What are the coordinated of the vertices of the square?
Alexxx [7]

<u>Answer</u>:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

The ratio of area of  larger square to smaller square is 9:1

<u>Step-by-step explanation:</u>

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1),  B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

To find the area of the small square

the side  of the small square is 2 units

so the are of the small square is 2^2 = 4 square units

To find the area of the larger square

lets find the side AB of the square using distance formula

=>\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}

=>\sqrt{(3 - (-3))^2 +(-3 - (-3))^2}

=>\sqrt{(3 +3)^2 +(-3 +3)^2}

=>\sqrt{(6)^2 +(0)^2}

=>\sqrt{36}

=>6

AB =6 units

In a square all the sides will be equal

Now the area of the larger square will be

6^2

36 square units

The ratio of larger square to smaller square is

=>36 : 4

=>9 : 1

5 0
3 years ago
Write an algebraic expression for the perimeter of a rectangular garden with a width of 3 metres and a length of 2y metres. Simp
anyanavicka [17]

Answer:

P = 2(2y+3)

P = 30

Step-by-step explanation:

P = 2 (L+W) or P = L + L + W + W

P = 2 (2y+3)

P = 4y+6

Plug in 6 for y.

P = 24+6

P = 30

5 0
2 years ago
In general, the median of a data set is less resistant to outliers than the mean. A. True B. False
Leto [7]
A. true, the median of a data set is less resistant to outliers than the mean
7 0
2 years ago
Read 2 more answers
Find the length of the missing side Geometry
leonid [27]

7.

Since it is a right triangle we can use Pythagorean Theorem to solve.

A^2+B^2=C^2

We are given C and B. We are solving for A, so we can input what we know.

A^2+24^2=25^2

A^2+576=625

A^2=49

A=7

Therefore, the missing side is equal to 7.

5 0
2 years ago
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