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3 years ago

15* Que Equations of lins - Part

Mathematics

1 answer:

Phantasy [73]3 years ago

4 0

There is not a given equation nor ordered pair, so it is impossible to answer this question. I apologise.

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The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

Margarita [4]

Answer:

$\angle PRQ = 80$

Step-by-step explanation:

Given

$\angle SPR = 145^o$

$\angle POT = 115^o$

See attachment

Required

Find $\angle PRO$

First, calculate $\angle RPO$

$\angle RPO + \angle SPR = 180$ --- angle on a straight line

So, we have:

$\angle RPO + 145 = 180$

Collect like terms

$\angle RPO = 180 - 145$

$\angle RPO = 35$

Next, calculate PQR

$\angle POR + \angle POT = 180$

So, we have:

$\angle POR + 115 = 180$

Collect like terms

$\angle POR = 180-115$

$\angle POR = 65$

So, PRO is calculated as:

$\angle PRO + \angle POR + \angle RPO = 180$ --- angles in a triangle

So, we have:

$\angle PRO + 65 + 35= 180$

$\angle PRO + 100= 180$

Collect like terms

$\angle PRO = 180-100$

$\angle PRO = 80$

3 0

3 years ago

Please don't troll.. I am in desperate need of help, I will give brainliest.

nalin [4]

Answer:

Step-by-step explanation:

-6x - 9/2

8 0

3 years ago

Read 2 more answers

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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3 years ago

n a word processing document answer the following question. How could you use Descartes' Rule and the Fundamental Theorem of Alg

notka56 [123]

<span>I will discuss polynomials. A polynomial can be classified according to the number of expressions that it has in a given equation. A monomial has only one expression having a coefficient (number) and a variable (letter). A binomial has two expressions, same as the definition of the monomial. And a trinomial has three expressions, same as the definition of a monomial. We can determine the degree of a polynomial by looking at the exponents of the given polynomial. If an expression has two variables with different exponents, you can add their exponent to determine their degree.

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3 0

3 years ago

Can someone please tell me if I am correct?

Olin [163]

Answer:

ur correct

Step-by-step explanation:

3 0

2 years ago