The answer is 10.
4 a + 5 b when a = 4 and b = - 1.2
Answer:
Perimeter of rectangle before folded = 56 in
Total area after folding = 156 sq in
Step-by-step explanation:
Rectangle before folded: l = 16 and w = 12
P = 2(16) + 2(12) = 32 + 24 = 56 in.
Figure after folding: Area of trapezoid + area of rectangle
Area of trapezoid = h(
)/2 = 6(4 + 16)/2 = 60
Area of rectangle = lw = 16(6) = 96
Total area after folding = 60 + 96 = 156 sq in.
Note: You could also find the area after folding by substracting the areas of the two triangles in the corners from the area of the original rectangle. Your choice. OK?
I'm pretty sure it is 72.42237223 ( that's before rounding)
Answer:
or Decimal 3.25
Step-by-step explanation:
Step 1: Flip the equation.
4x=13
Step 2: Divide both sides by 4.

Answer:
or Decimal 3.25
hope this helps
Answer:
58 in^2
Step-by-step explanation:
The area of one face of the 3" cube is (3 in)^2 = 9 in^2. Then the 6 faces of that will have an area of ...
6·9 in^2 = 54 in^2
The area of the top of the paperweight is unaffected by the area of the added cube: the area the smaller cube covers is exactly the same as its exposed top area. So, the net effect of the added 1" cube is to increase the total area by that cube's lateral area: 4 faces at 1 in^2 for each face, a total of 4 in^2.
Then the total surface area of the paperweight is ...
54 in^2 + 4 in^2 = 58 in^2