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IceJOKER [234]
3 years ago
6

Errors in the programming language Python can be broadly classified into two types, syntax errors, and logical errors. When writ

ing a program the first time, the probability for syntax errors to arise is 0.3, that for logical errors is 0.5, and that for both errors to occur is 0.1.(a) Find the probability that no syntax errors occur.(b) Find the probability that no errors occur.(c) Find the probability that errors of any type occur.(d) The programmer found a syntax error in the code. What is the probability that there are also logical errors based on this finding?(e) Are the events of having syntax errors and logical errors independent? Also, explain why.
Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

Step-by-step explanation:

a( Pr(no syntax error) = 1-Pr(syntax error arises)

Pr(no syntax error) = 1 -0.3

Pr(no syntax error) = 0.7

b) Pr(no error occurred) = 1-Pr(both error occurred)

Pr(no error occurred) = 1-0.1

Pr(no error occurred) = 0.9

c) Pr(any type of error occurred) = Pr(syntax error occur)+Pr(logical)

Pr(any type of error occurred) = 0.5+0.3 = 0.8

d) Pr(syntax and logical) = Pr(syntax occur)+Pr(logical or syntax occur)

= 0.3+0.1

= 0.4

e) Independent event are events that occurs at the same time. The occurrence of one does not affect the other.

Pr(logical and syntax) = pr(syntax)×pr(logical)

Given

pr(syntax)×pr(logical) = 0.3×0.5 = 0.15

From the question, Pr(logical and syntax) = Pr(both error occurred) = 0.1

Since Pr(logical and syntax) ≠ pr(syntax)×pr(logical), this means that the errors are not independent

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Neporo4naja [7]

Answer: 8 batches

Step-by-step explanation:

To get the number of batches she made, we can just use proportion to solve it. But first, we need to convert 5 1/3 to improper fraction

5 1/3 = 16/3

Then we can now use the proportion to solve

2/3 cups = 1 batch

16/3 cups = x (note:5 1/3=16/3)

cross multiply

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we need to make x the subject of the formula, to do that we will multiply each side of the equation by 3/2

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2 years ago
if the first and third of three consecutive odd integers are added, the result is 75 less than five times the second integers. f
Anastaziya [24]

Answer:

<em>The third integer is 27</em>

Step-by-step explanation:

Given

Represent the consecutive odd numbers with T_1, T_2; and\ T_3

Since they are consecutive odds, then

T_2 = 2 + T_1

T_3 = 2 + T_2

<em>From the first statement in the question, we have that</em>

T_1  + T_3 = 5 T_2 - 75

Required

Find the third integer

Recall that

Substitute T_2 = 2 + T_1 in T_3 = 2 + T_2

T_3 = 2 +  2 + T_1

T_3 = 4 + T_1

Substitute T_3 = 4 + T_1 and T_2 = 2 + T_1 in T_1  + T_3 = 5 T_2 - 75

T_1  + 4 + T_1 = 5(2 + T_1) - 75

Open Brackets

T_1  + 4 + T_1 = 10 + 5T_1 - 75

Collect like terms

T_1 + T_1 + 4  = 5T_1 - 75 + 10

2T_1 + 4  = 5T_1 - 65

Collect like terms

2T_1  -  5T_1  = - 65 - 4

-3T_1   = - 69

Divide both sides by -3

\frac{-3T_1}{-3}   = \frac{- 69}{-3}

T_1 = 23

Recall that T_3 = 4 + T_1

T_3 = 4 + 23

T_3 = 27

<em>The third integer is 27</em>

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Place a check mark in the box next to each expression that is equivalent to 4^3
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B, d, e, f

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