When choosing an interval to use for a frequency table, the low value and the high value of the dat is considered so that the interval refrects a true data size for all the intervals.
Given that a<span>
data set has values ranging from a low of 10 to a high of 52. Using the class limits of 10-19, 20-29, 30-39, 40-49 for a
frequency table will make the last interval not to refrect the true size of the other intervals. i.e. the last interval will be 50 - 52 which has a size of 3, different from the size of 10 the other intervals have.</span>
Answer:
1.4×10^-1 inches is the length of the new tear
Step-by-step explanation:
(1.4×10^-4) ×1000 =0.14
In scientific notation 1.4×10^-1
How to find IQR:
Find the median of the lower and upper half of your data. Subtract Q3 - Q1 to determine the IQR.
1st Quartile- 125
3rd quartile- 242.5
Median-192
Interquartile Range -117.5 (242.5 - 125)
Answer:
y ≤ 5/2x + 7
Step-by-step explanation:
Rearrange the inequality so it looks like y = mx+b or in other terms, the y is on the left and everything else is on the right.
5x - 2y ≥ -14
-5x -5x
-2y ≥ -5x - 14
/-2 /-2 /-2
y ≤ 5/2x + 7
i changed the direction of the inequality sign because i divided everything by a negative 2.
Answer:
1,2,3,4,5,6,7,8,9,10,11
Step-by-step explanation:
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