When testing for differences between treatment means, a confidence interval is computed with __________________?
1 answer:
The confidence interval is based on mean square error. T<span>he </span>mean squared error<span> (</span>MSE<span>) </span><span>of an </span>estimator<span> measures the </span>average<span> of the squares of the </span>errors<span> or </span>deviations.<span> MSE is calculated by the formula attached in the picture, where Xbar is a vector of predictions, X is the vector of predicted values. </span>
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Answer:
t Subscript alpha divided by 2 = 2.921
Step-by-step explanation:
With sample sizes lower than 30, we use the t-test.
Otherwise, we use the z-test.
Here, n = 17
So we use the t-test.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 17 - 1 = 16
Now, we have to find a value of T, which is found looking at the t table, with 16 degrees of freedom(y-axis) and a confidence level of 0.99(). So we have T = 2.921
So the correct answer is:
t Subscript alpha divided by 2 = 2.921
Answer:
The coordinate of the rest stop is:
The distance between the hotel and the stadium is 32 miles
Step-by-step explanation:
Given
--- Team hotel
--- Stadium
Solving (a): The coordinates of the rest stop
The rest stop is at half way;
So, the coordinate is:
This gives:
Open bracket
Solving (b): Distance between the hotel and the stadium
We have:
--- Team hotel
--- Stadium
The distance (d) is:
So, we have:
From the question, we have:
So: