Answer:For those problems USE PHOTOMATH it is your algebra savior!
Step-by-step explanation:
Answer:
1. 5/12
2. 0
Step-by-step explanation:
1. S, <u>E</u>, M,<u> I</u>, T, R,<u> O</u>, P,<u> I</u>, C,<u> A</u>, L
( underlined letters are vowels)
there are 5 vowels out of 12 letters= 5/12
2. There is no 0 on a standard cube, therefore the answer is 0
Answer:
attached below
Step-by-step explanation:
Assuming that Y1 and Y2 are independent exponential random variable with mean 3
where : U = Y1 + Y2 applying the property of exponential distribution sum of exponentials will follow a gamma distribution
i.e. ∝ = 2 , and β = 1
note : U = 2X
Hence probability distribution function X =
Fx (x) = p( X ≤ x )
= p( U ≤ 2x )
= Fu (2x)
probability density function X
f (x) =
= 2 Fu (2x)
attached below is the remaining part of the solution
![\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+4}x\stackrel{\stackrel{c}{\downarrow }}{+12} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{4}{2(1)}~~,~~12-\cfrac{4^2}{4(1)} \right)\implies (-2~~,~~12-4)\implies (-2~,~8)](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertex%20of%20a%20vertical%20parabola%2C%20using%20coefficients%7D%20%5C%5C%5C%5C%20f%28x%29%3D%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B1%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B4%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B%2B12%7D%20%5Cqquad%20%5Cqquad%20%5Cleft%28-%5Ccfrac%7B%20b%7D%7B2%20a%7D~~~~%20%2C~~~~%20c-%5Ccfrac%7B%20b%5E2%7D%7B4%20a%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28-%5Ccfrac%7B4%7D%7B2%281%29%7D~~%2C~~12-%5Ccfrac%7B4%5E2%7D%7B4%281%29%7D%20%5Cright%29%5Cimplies%20%28-2~~%2C~~12-4%29%5Cimplies%20%28-2~%2C~8%29)
well, the quadratic has a leading term with a positive coefficient, meaning is a parabola opening upwards, like a "bowl", comes from above down down down, reaches a U-turn, namely the vertex, and goes back up up up.
so the minimum value is at the vertex of course, and the minumum is well, just the y-coordinate of the vertex, 8.
8 post 4ft is the length 2ft ,yes if you dived 5 from 40 that is how many post , then you dived how many posts and that is the height then you dvide that and that is your width.