Answer:
13
Step-by-step explanation:
AB = 20
DE =12
Since AB and DE bisect each other, therefore:
AC = CB = ½(AB)
AC = CB = ½(20)
AC = CB = 10
Also,
DC = CE = ½(DE)
DC = CE = ½(12)
DC = CE = 6
Since F is the midpoint of DC, therefore:
FC = ½(DC)
FC = ½(6)
FC = 3
Find the value of FC + CB. Plug in the values of FC and CB:
3 + 10 = 13
I would say increasing
prove me wrong
Slope = -2
Y intercept = 4
Equation. y = -2x +5
Using points, (1,2) and (3,-2)
Slope = (-2-2)/(3-1) = -4/2 = -2
-2 = (y-3)/(x-1)
-2(x-1) = y-3
-2x +2 = y-3
y = -2x +2 +3
y = -2x +5
The possible solutions are 58 degree, 122 degrees, 302 degrees and 238 degrees
Please see the attachment
From the figure, it is evident that
cos AOB = OB/OA = 53/100 = 0.53
Thus, cos-1 (0.53) = 58 degrees
AOB = 58 degree
Also, there are can be other values depending on the quadrants
COB = 180 -58 = 122 degrees
FOB = 360 -58 = 302 degrees
EOB = 180 + 58 = 238 degrees
7x+90+20=180
7x+110=180
7x=180-110
7x=70
7x/7 = 70/7
X=10
Y=40
