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4 years ago

12

Robert works in a toll booth. About 18 to 23 cars pass through Robert's booth every 23 minutes. Which is a reasonable estimate f

or the number of cars that pass through Robert's booth in 69 minutes?

1 answer:

BARSIC [14]4 years ago

8 0

A reasonable number between 18 and 23 is 20. 69 minutes is 3 times 23 minutes, so we multiply the 20 by 3, getting an estimate of 60 cars.

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Is 3.03003000300003... a repeating decimal

SVETLANKA909090 [29]

The answer is no because after each 3 there is one more zero added

to be repeating the number of zeros would have to stay the same

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3 years ago

The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel:

Stels [109]

Answer:

SAS postulate

Step-by-step explanation:

In the figure attached, quadrilateral ABCD is shown.

The Side Angle Side (SAS) postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

AB is congruent to DC, and DB is the side common to triangles ABD and BCD. The included angle between sides AB and DB is angle ABD which is congruent with angle BDC, the angle included between sides DB and DC.

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3 years ago

What is the approximate volume of the sphere?

Vinvika [58]

C. 523.33

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3 years ago

Read 2 more answers

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago

Thank you so much!! If u get this right I'll mark you!

Semenov [28]

Hi! I hope you are having a great day! So looking here at this question I do so humbly believe that your answer is Number to and or B. all numbers Less than 7. <em>(seven) ==> ♥</em>

Explanation for Q.A.:

The sign is to the right (<)
If x = < 7 then it is evidently going to be B. (LOL)
You are, Awesome! and I am to so yea... It is going to be right! trust me.

I hope that this is helpful to you! I also pray that you get a 100% Good luck.`♥

4 0

3 years ago