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2 years ago

1) How do you find the sum of the exterior angle measures of any convex polygon?

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

8 0

Answer:

1) sum of all convex polygons' EXTERIOR ANGLES IS ALWAYS 360 DEGREES. If it is a triangle or even if it is a 25- gon.

2) if the polygon is regular then this means all of the sides are equal and all of the angles are equal to each other.

for example: Find the measure of an exterior angle of a REGULAR HEXAGON. so a regular hexagon has 6 sides all the same length and 6 exterior angles all the same measures. so to find the measure of 1 exterior angle you do 360 degrees /6 = 60 degrees. so an exterior angle of a regular hexagon is 60 degrees.

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a piece of paper has side lengths of 11 inches and 8 inches . what is the perimeter of the piece of paper ?

inysia [295]

The answer is 30 be 11+11+8+8

8 0

3 years ago

Read 2 more answers

A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION <br> 6

nata0808 [166]

Answer:

Step-by-step explanation:

Assuming this is a trapezoid,

$\frac{29+WZ}{2}=37 \\ \\ 29+WZ=74 \\ \\ WZ=45$

5 0

2 years ago

Fulton Gardens buys 6,300 flower bulbs. If 70 bulbs can be planted in each flower bed, how many flower beds are needed to plant

ki77a [65]

Answer:

Step-by-step explanation:

6300/70=90

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3 years ago

Jada purchases movie tickets online. She buys 2 tickets for adults and 4 tickets for children. The cost of a ticket for a child

grandymaker [24]

Answer:

Step-by-step explanation:

58 is the answer without tax

so the cost of an adult ticket is 13 dollars

and the kids ticket is 8 dollars

use system of equations to solve this.

58=2x+4y

y=x-4

8 0

3 years ago