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pochemuha
3 years ago
10

Toni stacks cube shaped beads that measure 1 centimeter on each edge in a storage box the box can hold six layers of 24 cubes wi

th no gaps or overlaps what is the volume of Tonys storage box
Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
The answer is 144 cm. 24*6 equals 144, so that would be the answer
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Reduce the fraction 3×15×24 /16×20×6 no links or files​
bagirrra123 [75]

Answer:

1 38888888889/50000000000

Step-by-step explanation:

The answer to the first part equation is 1080 ( 3*15*24). The answer to the second question ( 16*20*6) is 1920. Then you divide 1920/ 1080= 1 38888888889/50000000000

6 0
2 years ago
What is the simplified expression for -3(2x-y)+2y+2(x+y)
JulijaS [17]

Answer:

7y - 4x

Step-by-step explanation:

Given

- 3(2x - y) + 2y + 2(x + y) ← distribute parenthesis

= - 6x + 3y + 2y + 2x + 2y ← collect like terms

= 7y - 4x

7 0
3 years ago
Brew Ha Ha Coffee produces two types of coffee blends: Morning,x,and House,y. The Morning blend has 9oz of a Guatemalan coffee a
Anastaziya [24]

Answer:

Fourth option

Step-by-step explanation:

When graphing the given inequalities you will get a region like the one shown in the attached image. This region is delimited by 4 straight

x = 0\\\\y = 0\\\\9x + 6y = 400\\\\7x + 10y = 400

The points indicated at the ends of the region are the maximum possible values of x and y.

We must test these points in the objective function P = 2x + 2.5y and see which point maximizes the value of P.

<em><u>Remember that the boundaries of the region are not included. </u></em>

We can prove the point <em>x = 0</em> and <em>y = 39</em> because (0,4) is not included in the region.

P = 2(0) + 2.5(39) = 97.5

Now we test the point <em>x = 33</em> and <em>y = 16 </em>

P = 2(33) + 2.5(16) = 106

Now we test the point <em>x = 44</em> and <em>y = 0</em>

P = 2(44) + 2.5(0) = 88

Finally the optimal value is:

<em>x = 33 oz</em>

<em>y = 16 oz </em>

With a gain of $106

8 0
3 years ago
4.1<br> Determine between which two whole numbers lies square root of 20
Schach [20]

The square root of 20 is between 4 and 5.

<h3>Whole Numbers</h3>

They are the numbers represented by positive real numbers where the fractions and decimal numbers are not included.

For solving this question, you should list the whole numbers whose your square is less than 30. Your list must present the following numbers:

0 ⇒ 0²=0

1 ⇒ 1²=1

2 ⇒ 2²=4

3 ⇒3²=9

4 ⇒ 4²=16

5 ⇒ 5²=25

Note that 6²=36, it is greater than 30,because of this it is not in the previous list.

The question asks to determine between which two whole numbers lies the square root of 20. Therefore, from the previous list, it is possible to see that the value 20 is between 16 and 25. The square root of 16 and 25 is equal to 4 and 5, respectively.

Thus, the square root of 20 is between 4 and 5. You can check this results in your calculator:\sqrt{20}=2\sqrt{5}=4.47

Learn more about the square root here:

brainly.com/question/35767

3 0
2 years ago
Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

7 0
3 years ago
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