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3 years ago

Will give brainliest!!!!!!!!!

Mathematics

2 answers:

anastassius [24]3 years ago

7 0

Answer:

The given diagram is a scatter plot in which temperature is plotted against number of visitors.

As the number of visitors is rising with the rise in temperature, its a positive correlation.

As joining the dots is going to give a web of line segments, it is not going to be helpful to understand the trends.

The best way to understand the trends is to make the line of best Fit in such a way that the number of dots on either side are approximately the same.

Thus this could represent the general trend

natima [27]3 years ago

3 0

The given diagram is a scatter plot in which temperature is plotted against number of visitors.

As the number of visitors is rising with the rise in temperature, its a positive correlation.

As joining the dots is going to give a web of line segments, it is not going to be helpful to understand the trends.

The best way to understand the trends is to make the line of best Fit in such a way that the number of dots on either side are approximately the same.

I have attached the figure for your reference of the line of best fit.

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A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Which is the length of x? 1 7/9 2 1/2 1 1/4 1 3/5

trapecia [35]

Answer:

option D. x = 1 3/5

Step-by-step explanation:

ratio and proportion

5 2

X multiply:

5x = 4(2)

5x = 8

x = 8 / 5

x = 1 3/5

5 0

3 years ago

Read 2 more answers

Help, please! :(

Mashutka [201]

Answer:

A. The greatest one year increase in tuition ocurred from 1997 to 1998.

Step-by-step explanation:

If you look at the graph, at the points above 1997 and 1998, you'll see that the dots are separated by two lines, not just one.

3 0

3 years ago

Tony has 7/8 of a candy bar he wants to split the bar into servings that are 3/10 of the bar how many servings can he make

Irina-Kira [14]

Answer:

35/12 servings

Step-by-step explanation:

(7/8)/(3/10)=(7/8)(10/3)=70/24=35/12

3 0

3 years ago

In a study of crime, the FBI found that 13.2% of all Americans had been victims of crime during a 1-year period. This result was

Mkey [24]

Answer: The lower bound of confidence interval would be 0.116.

Step-by-step explanation:

Since we have given that

p = 13.2%= 0.132

n = 1105

At 90% confidence,

z = 1.645

So, Margin of error would be

$z\sqrt{\dfrac{p(1-p)}{n}}\\\\=1.645\times \sqrt{\dfrac{0.132\times 0.868}{1152}}}\\\\=0.0164$

So, the lower bound of the confidence interval would be

$p-\text{margin of error}\\\\=0.132-0.0164\\\\=0.116$

Hence, the lower bound of confidence interval would be 0.116.

3 0

3 years ago