3 years ago

In tossing a fair coin, what is

Mathematics

1 answer:

mafiozo [28]3 years ago

6 0

Answer:

1/64

Step-by-step explanation:

We want a second H in the 9th toss. So, we must get only 1 H in the first eight tosses.

So, in the first 8 tosses, we have 1 H and 7 T. Number of ways of getting 1 H and 7 T is 8!/7! = 8

Total possible outcomes = 2^9 = 512

Required probability = 8/512 = 1/64

[ If there is any problem with the solution, please inform me ]

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