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2 years ago

What is the surface area of this

Mathematics

1 answer:

DochEvi [55]2 years ago

8 0

Answer:

814 in ^2

Step-by-step explanation:

2(wl x hl x hw)

hope this helps

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Help me please answer thanks

lara31 [8.8K]

Answer: (2,4)

Explanation: I hope this is what the question is asking for because I am in 9th grade hope this helps and I hope I am right

3 0

2 years ago

So if each equation for x x / a - 5 equals B

Akimi4 [234]

Answer:

Sorry ineed point ehhh thnks po sa points:)

6 0

2 years ago

PLEASE HELP MEEEEE

ElenaW [278]

Answer:

t ≥ -12

Step-by-step explanation:

Divide the inequality by the coefficient of t. Because that value is negative, the sign gets reversed.

(-4t)/(-4) ≥ (48)/(-4)

t ≥ -12

5 0

3 years ago

Evaluate each of the following. help plz

Mariulka [41]

Answer:

5!= 120

13!= 6227020800

12!/6!= 665280

10!/7! 3!= 120

5(4!)= 120

Step-by-step explanation:

7 0

3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago