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svp [43]
4 years ago
15

2x3+4X(3X-1+2)-2x3+(12/3)X-3-X

Mathematics
1 answer:
grin007 [14]4 years ago
7 0

Answer:

0

Step-by-step explanation:

i think thats the answer sry if its wrong mate

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YES. She is correct.

\dfrac{x}{16}=4\qquad\text{multiply both sides by 4}\\\\\not\!4^1\cdot\dfrac{x}{16\!\!\!\!\!\diagup_4}=4\cdot4\\\\\dfrac{x}{4}=16

Equations are equivalent

Their solutions:

\dfrac{x}{16}=4\qquad\text{multiply both sides by 16}\\\\x=4\cdot16\\\\\boxed{x=64}\\----------\\\\\dfrac{x}{4}=16\qquad\text{multiply both sides by 4}\\\\x=16\cdot4\\\\\boxed{x=64}


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