Question

Can anyone give me the answer for this and how to do it I’m lost

Answer 1

The answer the i got was -2(5y-27). The simplified answer is -10y+54.
You distribute 32 and -32 through the parentheses, reduce the fraction with 2. Collect like terms: 12y+24-32y+32+10y-2 = -10y+24+32-2. Collect the sum- and you get -10y+54

Answer 2

Answer :

$\circ\sf\:32{\huge(}\dfrac{3y}{8}+\dfrac{3}{4}{\huge)}-32(y-1)-32{\huge(}-\dfrac{5y}{16}+\dfrac{2}{32}{\huge)}$

$\circ\sf\:{\huge(}\dfrac{(3\times 32)y}{8}+\dfrac{(3\times 32)}{4}{\huge)}-(32y-32)-{\huge(}-\dfrac{(5\times 32)y}{16}+\dfrac{(2\times 32)}{32}{\huge)}$

$\circ\sf\:[(3\times 4)y+(3\times 8)]-32y+32+(5\times 2)y-2$

$\circ\sf\:12y+24-32y+32+10y-2$

$\circ\sf\:(12y-32y+10y)+(24+32-2)$

$\circ\sf\:54-10y$

$\circ\:\boxed{\bf{\purple{2(27-5y)} }}$