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Romashka-Z-Leto [24]
2 years ago
11

Write the equation of the line that has slope -4 and y-intercept -2

Mathematics
2 answers:
Art [367]2 years ago
8 0

Answer:

-4+y=-2

Step-by-step explanation:

vladimir2022 [97]2 years ago
3 0
Equation is.... y= -4x-2
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Solve the system of equations<br> −4x+3y=−2 <br> y=x−1 ​ <br><br> x = <br> y =
dolphi86 [110]
Answer: x = -1 and y = -2

Step-by-step explanation:

So if you know y = x-1 you can plug that in where y is in the first equation

-4x + 3(x-1) = -2

Distribute the 3:

-4x +3x -3 = -2

Combine like terms:
-x -3 = -2

Add 3 to both sides:
-x = 1

Multiply by -1:
X = -1

Then you plug that into the other equation to get y=(-1)-1

Which is -2
4 0
3 years ago
There are (42)3 ⋅ 40 horses on a stud farm. What is the total number of horses on the farm?
Doss [256]

Answer:

5040

Step-by-step explanation:

When a number is in the Parenthesis that means you multiply. First you do 42*3 The answer would be 126. Since there is another Multiplication sign you just plug in your quotient (answer) into the problem. Now the equation is 126*40. 126*40=5040

6 0
2 years ago
Subtract and reduce: 2 2/3 - 1 1/2
babunello [35]

Step-by-step explanation:

I used a calculator but the answer is 1 1/6

5 0
2 years ago
The evolutionary pathways of ten different species are represented in the diagram below. SA Which two species are the most close
mr Goodwill [35]

Answer:

I don't see an O in the picture at all.

but here's how you solve it: just count the nodes between the species, the fewer the closer

I would go for E and I, only one step between them

3 0
3 years ago
Look at this cone:<br><br>,,
Assoli18 [71]
  • Slant height=l=3ft
  • Radius=r=2ft

We know

\boxed{\sf \star TSA_{(Cone)}=\pi r(r+\ell)}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=2 \dfrac{22}{7}\times 2(2+3)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{44}{7}(5)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{220}{7}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=31.4ft^2

Now

  • New slant height =2(3)=6cm
  • New radius=2(2)=4cm

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{22}{7}\times 4(4+6)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{88}{7}(10)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{880}{7}

\\ \sf\longmapsto TSA_{(New\:Cone)}=125.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{125.7}{31.4}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cone)}}:{TSA_{(Old\:Cone)}}=4:1}}}

7 0
2 years ago
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