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erma4kov [3.2K]
3 years ago
5

What is the sum of 1-2 and V-18?

Mathematics
2 answers:
Rufina [12.5K]3 years ago
7 0
Y-19 is the answer. You add the expressions
Snezhnost [94]3 years ago
4 0
Their is not enough detail to answer the question
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Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b
Ronch [10]
\32a^3b^2 \ , \  44ab^3 \ , \  40a^2b\\


\text {Taking out common factor : } \\ \\
4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)

\text { greatest common factor =  } 4ab
3 0
3 years ago
Alice earns simple interest on a principal of $1,400 at an annual interest rate of 6% for the period of 3 years. What equation s
Greeley [361]

The amount of interest is $252. The equations  or  represent the relation relationship between p, (r), (t) and (i).

Step-by-step explanation:

The formula of simple interest is

Where, principal amount (p), rate of interest (r), period of investment in years (t), and interest earned (i).

The principal amount is $1,400, interest rate of 6% and the time period of 3 years.

The amount of interest is

Therefore the amount of interest is $252.

The equations  or  represent the relation relationship between p, (r), (t) and (i).

5 0
2 years ago
Read 2 more answers
Please<br> Help fast I have 25 mins left
castortr0y [4]

Answer:

Step-by-step explanation:

sales earning commission=130,000-21000=109,000

sales commission=5800-900=4900

rate of commission=4900/109,000 ×100=490/109 %

≈4.495

≈4.50%

4 0
3 years ago
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances
wariber [46]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to compare two compounds, designed to reduce braking distance, used in tire manufacturing to prove if the braking distance of SUV's equipped with tires made with compound 1 is shorter than the braking distance of SUV's equipped with tires made with compound 2.

So you have 2 independent populations, SUV's equipped with tires made using compound 1 and SUV's equipped with tires made using compound 2.

Two samples of 81 braking tests are made and the braking distance was measured each time, the study variables are determined as:

X₁: Braking distance of an SUV equipped with tires made with compound one.

Its sample mean is X[bar]₁= 69 feet

And the Standard deviation S₁= 10.4 feet

X₂: Braking distance of an SUV equipped with tires made with compound two.

Its sample mean is X[bar]₂= 71 feet

And the Standard deviation S₂= 7.6 feet

We don't have any information on the distribution of the study variables, nor the sample data to test it, but since both sample sizes are large enough n₁ and n₂ ≥ 30 we can apply the central limit theorem and approximate the distribution of both variables sample means to normal.

The researcher's hypothesis, as mentioned before, is that the braking distance using compound one is less than the distance obtained using compound 2, symbolically: μ₁ < μ₂

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

The statistic to use to compare these two populations is a pooled Z test

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } }

Z ≈ N(0;1)

Z_{H_0}= \frac{69-71-0}{\sqrt{\frac{108.16}{81} +\frac{57.76}{81} } }= -1.397

The rejection region if this hypothesis test is one-tailed to the right, so you'll reject the null hypothesis to small values of the statistic. The critical value for this test is:

Z_{\alpha  } = Z_{0.05}= -1.648

Decision rule:

If Z_{H_0} > -1.648 , then you do not reject the null hypothesis.

If Z_{H_0} ≤ -1.648 , then you reject the null hypothesis.

Since the statistic value is greater than the critical value, the decision is to not reject the null hypothesis.

At a 5% significance level, you can conclude that the average braking distance of SUV's equipped with tires manufactured used compound 1 is greater than the average braking distance of SUV's equipped with tires manufactured used compound 2.

I hope you have a SUPER day!

4 0
3 years ago
Caroline bought 20 shares of stock at 101/2, and after 10 months the value of the stocks was 111/4. If Caroline were to sell all
SashulF [63]
The correct answer would be C. $15.

Hope helps
8 0
3 years ago
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