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hjlf
3 years ago
6

Trying to group factor an equation, n^2-3b^2+nb-3n

Mathematics
2 answers:
REY [17]3 years ago
6 0

Answer:

n(n - 3) + b(n - 3b)

Step-by-step explanation:

n^2 - 3b^2 + nb - 3n =

Rearrange the terms in a way in which you have two terms with a common factor and another two terms with a common factor.

= n^2 - 3n + nb - 3b^2

Now factor a common factor out of each two terms.

= n(n - 3) + b(n - 3b)

soldier1979 [14.2K]3 years ago
4 0

Answer:

n(n-3)+b(n-3b)

Step-by-step explanation:

n^2-3b^2+nb-3n

Lets group the terms that has same variables and try to factor

Rearrange the terms

n^2-3n-3b^2+nb

Group first two terms and last two terms

(n^2-3n)+(nb-3b^2)

Factor out 'n' from the first group and 'b' from the second group

n(n-3)+b(n-3b)

Here there is no common factor . So this cannot be factored further

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