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Talja [164]
3 years ago
6

You are employed as a network administrator at Widget. The Widget network is TCP/IP based. You have been instructed to configure

Dynamic Host Configuration Protocol (DHCP) on Widget’s network.What steps would you follow?
Computers and Technology
1 answer:
wolverine [178]3 years ago
7 0

DHCP operations fall into four phases: server discovery, IP lease offer, IP lease request, and IP lease acknowledgement. These stages are often abbreviated as DORA for discovery, offer, request, and acknowledgement.

Explanation:

  • DHCP provides reliable IP address configuration, while reducing network administration.
  • Discovery : The DHCP client broadcasts a DISCOVER message on the network subnet using the destination address or the specific subnet broadcast address.  A DHCP client may also request its last known IP address
  • Offer :When the server receives a DISCOVER message from a client, which is an IP address lease request, the DHCP server reserves an IP address for the client and makes a lease offer by sending a OFFER message to the client.
  • Request : In response to the DHCP offer, the client replies with a REQUEST message, broadcast to the server,[a] requesting the offered address.
  • Acknowledge : When the DHCP server receives the REQUEST message from the client, the configuration process enters its final phase. The acknowledgement phase involves sending a ACK packet to the client.
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python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
Artyom0805 [142]

Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

 pets = 0

 item = 0

 item_Cost = 0

 #set the while loop

 while(i < nItems):

   #check the items of the variable

   if isPet[i]:

     #add and initialize in the cost

     cost += prices[i]

     #increament in the variable by 1

     pets += 1

   #otherwise

   else:

     #add and initialize in the item_Cost

     item_Cost += prices[i]

     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

   i += 1

 #check the pet is greater than equal to 1  

 #and item is greater than equal to 5

 if(pets >= 1 and item >=5):

   #then, print the message

   print("You receive discount")

   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

   #print the message

   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

     # then, add in the pet

     pet.append(True)

   #otherwise

   else:

     #not add in the pet

     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
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3 years ago
Analyze the code and identity the value of variable a,b and c after the code execution. int a=40, b=50, c=60; if(! (a&gt;=40)) b
AlekseyPX

Answer:

a=40,b=30,c=60

The answer is B

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What is a flowchart and write it's work​
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Answer: A flowchart is a type of diagram that represents an algorithm, workflow or process. The flowchart shows the steps as boxes of various kinds, and their order by connecting the boxes with arrows. ... Flowcharts are used in analyzing, designing, documenting or managing a process or program in various fields.

Explanation: brainliest plz!

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Which computer are used by mobile employees such as meter readers.​
Naily [24]

Answer:

Handheld/Mobile Computers

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Read 2 more answers
let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest va
Ahat [919]

Answer:

Explanation:

From the given information:

a_{n-1} , a_{n-2}...a_o in binary is:

a_{n-1}\times 2^{n-1}  + a_{n-2}}\times 2^{n-2}+ ...+a_o

So, the largest number posses all a_{n-1} , a_{n-2}...a_o  nonzero, however, the smallest number has a_{n-2} , a_{n-3}...a_o all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

(11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}

= \dfrac{1(2^n-1)}{2-1}

\mathbf{=2^n -1}

(1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}

\mathbf {= 2 ^{n-1}}

Hence, the smallest value is \mathbf{2^{n-1}} and the largest value is \mathbf{2^{n}-1}

3 0
2 years ago
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