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3 years ago

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1 answer:

zepelin [54]3 years ago

5 0

A way to write this would be:
100 - e = 42

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PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

Using all of the following numbers once, 8,8,3,5 how do u get 10

Sveta_85 [38]

Lol this is hard try using multiplication or division...

8 0

3 years ago

-10 + 10у + -3y +7<br>does anyone know the answer plz??????<br>

PilotLPTM [1.2K]

☁️ Answer ☁️

I got: 7y - 3

Hope it helps.

Have a nice day hyung!~ ￣▽￣❤️

8 0

3 years ago

Read 2 more answers

Yoda purchases a light saber for $1,678 with an installment loan that has an APR of 12%. The store financing requires a 15% down

yan [13]

Answer:$2,000

Step-by-step explanation:

4 0

3 years ago

William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot

Tanzania [10]

Answer:

The zero of the equation represents the maximum height attained by the shot put.

Step-by-step explanation:

William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot from the ground is

H = $-2x^{2}+3x+5$

We can find the zeroes of these two equations.

For that put H = 0.

$-2x^{2}+3x+5$ = 0

(-2x + 5)(x + 1) = 0

x= -1 or x = 2.5

x= -1 is neglected as it is not practical.

x = 2.5 is the maximum height attained by the shot put.

The zero of the equation represents the maximum height attained by the shot put.

6 0

3 years ago