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Blababa [14]
3 years ago
12

Fill in the blank: Type your answer in the box and then click "submit."

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
A way to write this would be:
100 - e = 42
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Joey throws a ball in the air. The graph shows the height of the ball on the y-axis and the time that the ball is in the air on
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Picture of the graph ?
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3 years ago
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Find the nth term <br> 26,19,12,5,-2<br><br> I will mark brainliest for the best answer :D
lara31 [8.8K]

Answer:

-9

Step-by-step explanation:

you're taking away 7 each time, so -2-7=-9

5 0
2 years ago
AWARDING BRAINLIEST HELP! The length of FH is 9 cm. What is the length of GK?
GarryVolchara [31]

Answer:

9 cm

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
PLZ HELP I WILL GIVE THE BRAINLEST AND 22 PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! An expression is shown below: 6(m + 2 +
n200080 [17]

Answer:

part A: expression 1: 6(8m+2)

          expression 2: 6m+12+42m

Part B: 6(m+2+7m)= 6(8m+2)

combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)

6(8m+2)= 6(8m+2)

Part C: 6m+12+42m=6(m+2+7m)

m=0

6(0+2+7(0))=6(0)+12+42(0)

6(2)= 12

12=12

7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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