Question

a rectangle has a primeter of 200 ft the length is 4 more feet than the width find the dimensions of the rectangle

Answer 1

The length and width of the given rectangle are 52 ft and 48 ft respectively.

Solution:

The relationship between the length and breadth is given as following:

The length is 4 more feet than the width

The perimeter of the rectangle is given as 200 ft.

The formula to find the perimeter of a rectangle is:

Perimeter = 2(length + width)

Let length and width of the rectangle be denoted as ‘L’ and ‘B’

The given relationship between length and width can be written in equation form as follows:

L = 4 + B ------ eqn 1

Substitute the value of "L" in perimeter of triangle

200 = 2(4 + B + B)

200 = 2(4 + 2B)

200 = 8 + 4B

4B = 192

B = 48

Since, we know the value of width lets substitute it in eq1 to find the length.

L = 4 + 48

L = 52

Therefore, the length and width of the given rectangle are 52 ft and 48 ft respectively.