3 years ago

Karen says every equilateral is acute. Is this true?

2 answers:

6 0

Yes is your answer for this problem.

4 0

Well from what i think yes a equilateral is what it is and must follow certain guidelines to be called one

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Papessa [141]

This is what I got. I don’t know if it’s 100% right but I think it is.

7 0

3 years ago

netineya [11]

Answer:

$\bold{y+1=5(x+1)}$

Step-by-step explanation:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(-1,\,-1)\ \implies\ x_1=-1\,,\ y_1=-1\\(0,\,4)\ \implies\ x_2=0\,,\ y_2=4\\\\m=\dfrac{4-(-1)}{0-(-1)}=\dfrac{5}{1}=5$

$y-y_1=m(x-x_1)$ - point-slope form of Equation of the Line

$x_1=-1\,,\ y_1=-1\,,\ m=5\\\\equation:\\{}\qquad\qquad y-(-1)=5\big(x-(-1)\big)\\\\{}\qquad\qquad y+1=5\big(x+1\big)$

6 0

3 years ago

denis23 [38]

Answer:

x=7 and y =2.

2x+y = 16

x+y = 9

3 0

3 years ago

Alex

9 + 6(4 + 4)

9 + 6(8)

9 + 48 = 57

6 0

4 years ago

astra-53 [7]

The X values are graphed horizontally, while the Y values are graphed vertically.

6 0

4 years ago