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likoan [24]
3 years ago
9

Mai is filling her fish tank. How many gallons of water will be in the fish tank after

Mathematics
1 answer:
tangare [24]3 years ago
3 0
This question makes no sense. We don’t know how many gallons the fish tank holds and we also don’t know the rat at which she is pouring.
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A SOLUTION CONTAINS 60% WATER, 15% BLEACH AND THE
Allushta [10]

Answer:

20 ounces of cleaner

Step-by-step explanation:

Water 48 oz is 60% of unknown total. 60% = 3/5. Create equation and solve

48= 3x/5. 240= 3x. 80 = x

Total of water, bleach and cleaner is 80 ounces

60% + 15% = 75%

100% - 75%= 25% cleaner

.25 × 80 = 20 ounces

6 0
2 years ago
Slope=5, goes through the point (2,7) what is the answer
Sidana [21]

Answer:

slope-intercept form: y=5x-3 point-slope form: y-7=5*(x-2)

Step-by-step explanation:

Y-y1=m(x-x1)

plug in the values and you get y=5x-3

7 0
2 years ago
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inessss [21]

You applied the rule improperly.  When dividing exponents, you subtract the exponent of the denominator <em>from</em> the exponent of the numerator, not the other way around.  The exponent you should have gotten was 8^{-6}

8 0
2 years ago
I need help, can anyone please help me?? I'll mark you BRAINLIEST if you answer correctly. :). Fill in the blanks.​
pav-90 [236]

(x+4)²=-63

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5 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
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