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3 years ago

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(1) The three salespeople for a local advertising firm are Lola, Ahmed, and Tommy. Lola sold $2030 in ads, Ahmed sold $1540, and

Tommy sold $1800. (a) What fraction of the total sales did each salesperson sell? (b) A $100 bonus was awarded to the three salespeople, which they had to share. It was awarded so that each salesperson received the same fraction of $100 as he or she sold of the total sales. How much did each person receive? Round to the nearest whole cent.

2 answers:

melamori03 [73]3 years ago

6 0

A.) First, you find the total sales. $2030 + $1540 + $1800 = $5370. Then, divide each with the total. The answer would be:

Lola: 203/537
Ahmed: 154/537
Tommy: 60/179

b.) Divide 100 by 3 for equal shares. Each person receives $33.3.

Eva8 [605]3 years ago

3 0

Answer: a) Fraction of the total sales did each salesperson sell:-

$\text{Lola}=\frac{203}{537}$

$\text{Ahmed}=\frac{154}{537}$

$\text{Tommy}=\frac{180}{537}$

b) Each person receive=$33

Step-by-step explanation:

Given: The three salespeople for a local advertising firm are Lola, Ahmed, and Tommy.

Sales by Lola= $2030

Sales by Ahmed=$1540

Sales by Tommy=$1800

Thus, the total sales= $2030+$1540+$1800=$5370

Fraction of the total sales did each salesperson sell:-

$\text{Lola}=\frac{\text{Sales by Lola}}{\text{total sales}}=\frac{2030}{5370}=\frac{203}{537}$

$\text{Ahmed}=\frac{\text{Sales by Ahmed}}{\text{total sales}}=\frac{1540}{5370}=\frac{154}{537}$

$\text{Tommy}=\frac{\text{Sales by Tommy}}{\text{total sales}}=\frac{1800}{5370}=\frac{180}{537}$

If $100 bonus was awarded to the three salespeople, then

Each person receive= $\frac{\$100}{3}=33.33\approx\$33$

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The sum of 5 consecutive numbers is -5. What is the largest out of the numbers?

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Verizon [17]

<h2>Steps:</h2>

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$\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84$

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

$f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}$

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

3 | 1 - 10 + 25 - 40 + 84
_________________

Firstly, drop the 1:

3 | 1 - 10 + 25 - 40 + 84
↓
_________________
1

Next, multiply 3 and 1, then add the product with -10:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3
_________________
1 - 7

Next, multiply 3 and -7, then add the product with 25:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21
_________________
1 - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12
_________________
1 - 7 + 4 - 28

Lastly, multiply -28 and 3, then add the product with 84:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12 - 84
_________________
1 - 7 + 4 - 28 + 0

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So right now, our equation looks like this:

$f(x)=(x-3)(x^3-7x^2+4x-28)$

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

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Now it can be rewritten as:

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<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

$f(x)=(x-3)(x^2+4)(x-7)$

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I believe the answer is d

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Tpy6a [65]

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Step-by-step explanation:

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