What happens to a line when the y-intercept is changed? Check all that apply. A.As the y-intercept increases, the graph of the l
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<span>4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
</span>Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9
<span>
x = - b </span>± √Δ / 2.a
A. Two real solutions (x' = -1 and x'' = -1/4)
a = 4; b = - 5, c = 1
</span>Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9
<span>
x = - b </span>± √Δ / 2.a
A. Two real solutions (x' = -1 and x'' = -1/4)
Answer:
- First, you want to divide the numerator and denominator by the cosine(x), and afterwards, it looks like this...
- Include 45 as one of the parameters and correlate with <em>tan</em>.
- Next, you want to multiply the numerator and denominator by the conjugate of the denominator, in this case, <em>tan x + tan 45.</em>
- Lastly, simplify, and you have the answer as <em>tan(45 + x)</em>