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3 years ago

How do you solve this equation?

Mathematics

1 answer:

Lerok [7]3 years ago

8 0

Answer:

p = A/(1 +rt)

Step-by-step explanation:

Combine terms using the distributive property, then divide by the coefficient of p.

A = p(1 +rt)

A/(1 +rt) = p

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What is the probability of rolling a 5 or not rolling a 5 using a regular 6-sided number cube?

Ne4ueva [31]

There are 6 different sides you can land on with a dice. So the probability of rolling any one side is 1/6. The probability of NOT rolling a 5 is the same thing as rolling anything except a 5. So that probability will be 5/6.

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3 years ago

Read 2 more answers

Assume that the random variable X is normally distributed with mean μ=80 and standard deviation σ=18. Find the 11th percentile f

choli [55]

<span>The value you are looking for is 70 - 8.4 = 61.6 Hope it helps

</span>

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3 years ago

debt payments of $800 due now and $1400 due in 5 months are to be repaid by a payment of $1000 in 3 months and a final payment i

loris [4]

Answer:

$1,304.70

Step-by-step explanation:

If interest 6% annually, monthly is 0.5%.

The debt in 5 months will be 800 plus compounded interest for 5 months plus new due debt

$800(1.005)^5+1400=2220.201$

In 3 more months the debt will be 2220.201 plus compounded interest for 3 months minus payment

$2220.201(1.005)^3-1000=1253.67$

After 8 months the debt would be 1253.67 plus compounded interest for 8 months

$2220.201(1.005)^3=1304.70$

Then the size of the final payment would be $1,304.70

5 0

3 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>