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Angelina_Jolie [31]
3 years ago
11

Divide 20m^2n^3 - 10m^2n by 5mn

Mathematics
1 answer:
Sonja [21]3 years ago
6 0

\frac{20 {m}^{2} {n}^{3}  - 10 {m}^{2}n  }{5mn}  \\  =   \frac{5mn(4m {n}^{2} - 2m) }{5mn}  \\  = 4 {m}^{2} n - 2m \\  = 2m(2mn - 1)

Hope this helps. - M
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Plz help me on this quick
Studentka2010 [4]

Answer: The third one

Step-by-step explanation: We can eliminate the first one right off the bat sinc we see that -4 has two outputs. Next, the graph's equation has no slope (x=3) so the input is all the same. Thirdly, the table shows a relationship between x and y and the numbers don't have a pattern that shows more than one output or input for a number. The fourth option are simply coordinates, it doesn't particularly tell us that all the coordinates are related to each other.

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2 years ago
PLEASE HELP ME PLEASE!!
erastova [34]

Answer:

Is that you in your pfp?

Step-by-step explanation:

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2 years ago
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Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
-9s - 8 = -4s + 8 - 3s
Olenka [21]
I wont solve this because Im to lazy, but I do recommend some of these sites to help you with your problem. MathPapa Algebra Calculator and PhotoMath. Hope this helps.
4 0
3 years ago
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A carpenter is putting a skylight in a roof. If the roof measures 10 + 8 by 8 + 6 and the skylight measures + 5 by 3 + 4, what i
Usimov [2.4K]

Answer:

The area is: 77x^2 + 105x + 28, option b.

Step-by-step explanation:

Rectangular area:

The area of a rectangular space is given bt the multiplication of its measures.

Area of the roof:

Dimensions of 10x + 8 and 8x + 6. So

A_{r} = (10x+8)(8x+6) = 80x^2 + 60x + 64x + 48 = 80x^2 + 124x + 48

Area of the skylight:

Dimensions of x + 5 and 3x + 4. So

A_{s} = (x+5)(3x+4) = 3x^2+4x+15x+20 = 3x^2 + 19x + 20

What is the area of the remaining roof after the skylight is built?

Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So

A_{r} - A_{s} = 80x^2 + 124x + 48 - (3x^2 + 19x + 20) = 80x^2 - 3x^2 + 124x - 19x + 48 - 20 = 77x^2 + 105x + 28

The area is: 77x^2 + 105x + 28, option b.

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