Answer:
(2P + G) feet/min
Step-by-step explanation:
Speed of the panda = P
Speed of the giraffe = P + G
Thus,
Speed of Panda + Speed of Giraffe = approaching time
= P + P + G
= <u>2P + G</u>
Thus, The panda and the giraffe are approaching each other at a rate
of <u>(2P + G) ft/min</u>
<u></u>
<em>Hope it helps :)</em>
Answer:
It's really easy just remember rise over run.
Step-by-step explanation:
so you rise 3 and run to the right 3
A great tip that helps me determine if it's positive or neagitve is if you go to the left then it's ALWAYS neagtive but if you go to the right then it's ALWAYS postive
Answer:
The variable Y represents the number of meters of string in the third yoyo
Step-by-step explanation:
In this equation y stands for the unknown variable. The equation tell you that hope made 3 different yo-yos so the number of yo-yos hope made isn't unknown, meaning, it cant be the first answer. The problem also tells you that hope used a total of 4 meters of string which means that the total number of string used isn't the unknown variable. The number of meters of string in the third yo-yo is the only number that isn't. This makes the number of sting used in the third yo-yo the unknown variable, making it y.
Answer:
4
Step-by-step explanation:
The rule of dilation is 
This means that each distance QX' is equal to 
where X is initial point and X' is its image after dilation.
Since QA=6, then
Answer:
The answer is 6
6(5)/8-3=
30/5=
=6
Step-by-step explanation:
