Answer:b)via radio signals
Explanation: Machine-to-machine technology is the technology that helps in sharing of the real time information of the device that have embedded sensor.They can work without the help of the manual factors.
The data is shared through the help of the radio signals in the devices like turbines vending machines etc for the tracking purpose and managing.
Thus the other options are incorrect because short distance is a disttance, cloud services are for the collection of services and databases contains the data. So, the correct option is option (b).
Answer:
A. f/2.8
Explanation:
A hole within a lens, through which light travels into the camera body is referred to as the APERTURE.
It is typically expressed as "f number" in photography. Basically, a fast lens is any lens with a maximum aperture of f/4 or more i.e f/2.8 , f/1.8 , f/1.4 etc.
The smaller the number is the bigger the maximum aperture is. Hence, the bigger the maximum aperture the more light that your lens will allow in.
Therefore, the ideal aperture settings for a fast lens is f/2.8
I suspect the answer they're looking for is false. However, as an experienced professional in learning and development, I can tell you that when done right these effects can enhance a presentation.
Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
