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4 years ago

Please help!!!!!! Hurry i only have 10 mins ill give brainy

Mathematics

1 answer:

Free_Kalibri [48]4 years ago

5 0

X3 because if it was anything else it would not be the same problem

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Constant rate of change

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Answer:

The constant rate of change is the average change that happens between a time period. In slope-intercept form, it is the mx part of the equation.

y = mx + b

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3 years ago

Read the excerpt from The Boy Who Harnessed the Wind by William Kamkwamba.

garik1379 [7]

Answer:

For this question I believe this is A) He is inventive and reasoursful.

Step-by-step explanation:

I think this is the answer because he made so many things like used bicycle tires to help him wire the wires in the text givin. Have a nice day and stay safe!!!

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4 years ago

A building is 3 ft from a 9-fence that surrounds the property. A worker wants to wash a window in the building 14 ft from the gr

kvv77 [185]

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3 years ago

What is 3(4 plus 7) -5•4 divided by 2

goblinko [34]

I am not positive, but I believe 23. sorry in advance if I’m wrong.

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4 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

3 years ago