Answer:
(0, -6)
Step-by-step explanation:
Given the following systems of linear equations;
3x - 2y = 12 ...... equation 1
16x - 4y = 24 ........ equation 2
We would solve for the solution using the elimination method;
Multiplying eqn 1 by 2, we have;
2 * (3x - 2y = 12)
6x - 4y = 24
16x - 4y = 24
Subtracting the two equations, we have;
(6x - 16x) + (-4y -[-4y]) = (24 - 24)
-10x - 0 = 0
-10x = 0
x = -0/10 = 0
Next, we would find the value of y;
3x - 2y = 12
3(0) - 2y = 12
0 - 2y = 12
-2y = 12
y = -12/2
y = -6
Check:
3x - 2y = 12
3(0) - 2(-6) = 12
0 - (-12) = 12
12 = 12
Note: the options provided for this questions are incorrect or inappropriate.
