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kozerog [31]
3 years ago
10

What is the solution to the following system of equations?

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

(0, -6)

Step-by-step explanation:

Given the following systems of linear equations;

3x - 2y = 12 ...... equation 1

16x - 4y = 24 ........ equation 2

We would solve for the solution using the elimination method;

Multiplying eqn 1 by 2, we have;

2 * (3x - 2y = 12)

6x - 4y = 24

16x - 4y = 24

Subtracting the two equations, we have;

(6x - 16x) + (-4y -[-4y]) = (24 - 24)

-10x - 0 = 0

-10x = 0

x = -0/10 = 0

Next, we would find the value of y;

3x - 2y = 12

3(0) - 2y = 12

0 - 2y = 12

-2y = 12

y = -12/2

y = -6

Check:

3x - 2y = 12

3(0) - 2(-6) = 12

0 - (-12) = 12

12 = 12

Note: the options provided for this questions are incorrect or inappropriate.

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Here is your answer

B. (12,30)

REASON:

Given,

y= 2x+6 .......(i)

3x-y= 6 .......(ii)

Putting the value of y from eq.i in eq.ii we get

3x-(2x+6)=6

3x-2x-6=6

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Putting x=12 in eq.i we get

y= 2x+6

y= 2×12+6

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y= 30

So,

\bold{x=12 and y= 30}

Hence answer is (12,30) in which x=12 and y=30

HOPE IT IS USEFUL

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