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irakobra [83]
2 years ago
12

A password contains exactly 7 letters. How many passwords are possible if letters cannot be used more than once?

Mathematics
2 answers:
DerKrebs [107]2 years ago
8 0

Answer:

B

Step-by-step explanation:

This is a combination problem. For the first letter, there are 26 possible letters in the alphabet to use. For the second, we cannot use the letter used in the first, so there are only 25 possible letters. Repeat this for the remaining 5 letters.

1st - 26

2nd - 25

3rd - 24

4th - 23

5th - 22

6th - 21

7th - 20

To find the number of possible passwords, simply multiply all these numbers together. 26*25*24*23*22*21*20 = 3,315,312,000. Therefore B is the correct answer.

aliya0001 [1]2 years ago
6 0

Answer:

B

Step-by-step explanation:

The answer is B

you can find answers for questions like these on quizlet.

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Answer:

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Step-by-step explanation:

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Step 1: Rearrange the datas in ascending or descending order if not arranged.

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Step 2:

We will locate the (N+1/4)the cumulative value of the data where N is the total frequency of the data.

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On cumulating the values up to the 21st value or more:

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4 years ago
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If it is #17 this:

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Step-by-step explanation:

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