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lara [203]
4 years ago
13

A floppy disc can store 1440000 bytes of data

Mathematics
1 answer:
max2010maxim [7]4 years ago
3 0

Answer:

1440000 = 1.44\times 10^{6}

We need approximately 1667 floppy disc to store 2.4\times 10^9 bytes of data.      

Step-by-step explanation:

We are given the following information in the question:

A floppy disc can store 1440000 bytes of data.

We have to convert  1440000 in a standard form.      

Standard Form:

  • Standard form is a way of writing down very large or very small numbers easily.
  • It helps us to express large numbers in powers of 10

The standard form can be written as:

1440000 = 1.44\times 10^{6}

We have positive power of 10 because we have to move to the right of the decimal point.

A hard disc can store 2.4\times 10^9 bytes of data.

Number of floppy disks needed to store the 2.4\times 10^9 bytes of data =

\displaystyle\frac{\text{Data Stored}}{\text{Data store by 1 floppy disk}}\\\\= \frac{2.4\times 10^9}{1.44\times 10^6} = 1.66667\times 10^{(9-6)} = 1.66667\times 1000 = 1666.67 \approx 1667

Thus, we need approximately 1667 floppy disc to store 2.4\times 10^9 bytes of data.

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Find the zero of each function and state the multiplicity of each zero. Please show all steps.
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Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.


Step-by-step explanation:

1. y=(x+3)^3

y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3

Zero: x=-3 multiplicity 3.


2. y=(x-2)^2 (x-1)

y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.

Zeros: x=2 multiplicity 2; x=1 multiplicity 1


3. y=(2x+3)(x-1)^2

y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.

Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

4 0
3 years ago
A potential buyer of the breed of snake known as a rattlesnake wishes to find the average weight and length of a full-grown rept
BlackZzzverrR [31]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
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3. Seth uses a bowl to fill a container with soil. The
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3/4 x 13/1 = 39/4 or 9 3/4 or 9.75
8 0
2 years ago
the area of a triangle is 6 and 3/8 square yards. The height of the triangle is 2 and 1/2 yards. What is the length of the base
Otrada [13]

Solution:

<u>Note that:</u>

  • Area of triangle = 6 3/8 yd²
  • Height of triangle = 2 1/2
  • Area of triangle = 1/2 x base x altitude

<u>Use the formula to find the base of the triangle.</u>

  • 1/2 x base x altitude = 6 3/8 yd²
  • => 1/2 x base x 2 1/2 = 6 3/8 yd²
  • => 1/2 x base x 5/2 = 6 3/8 yd²
  • => 5/4 x base = 6 3/8 yd²
  • => base = 6 3/8 ÷ 5/4 yd
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  • => base = 51/2 x 1/5 yd
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8 0
2 years ago
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Suppose that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 17. Using the empirical rul
a_sh-v [17]

Answer:

99.7% of IQ scores are between 46 and 148.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 97, standard deviation of 17.

What percentage of IQ scores are between 46 and 148?

97 - 3*17 = 46

97 + 3*17 = 148

Within 3 standard deviations of the mean, so:

99.7% of IQ scores are between 46 and 148.

5 0
4 years ago
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