Simplify 9 to the power of 2 over 9 to the power of 7
1 answer:
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Answer:
Step-by-step explanation:
Remember the general form of a linear equartion: y=mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).
The equation of line v (y=9x+1) has a slope of 9. A perpendicular line with have a slope equal to the negative inverse of the reference line. So the line we want will have a slope of -(1/9). That gives us y = -(1/9)x + b. Any vale of b will produce a line that is perpendicular. But we want a line that goes through point (3,-2). All we need to do is find a value for b that will make that wish come true.
Use the point (3,-2) in y = -(1/9)x + b and solve for b:
y = -(1/9)x + b
-2 = -(1/9)*(3) + b
-2 = -(1/3) + b
b = - 1 2/3, or -(5/3)
The equation is y = -(1/9)x + - (5/3)
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is. 
. 
. 
. The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same. In other words, we cannot add the square root of 4 to the square root of 5. They either both have to be 4 or they both have to be 5. So here's what we have thus far: 
. We can add 
and 
to get 
. That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.