Period of unusually high temperatures
2 answers:
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Answer:
water it yield is 244290.45 ft
Explanation:
given data
specific storage SS = 2.4 × ft
thickness b = 300 ft
water declined ΔH = 4.8 ft
radius r = 1,500 ft
to find out
How much water would it yield
solution
we know that
volume of water is
Vw = S × Area × ΔH ..............1
here S = specific storage × thickness
S = 2.4 × × 300
S = 7.2 ×
and
area = πr² = π 1,500² = 7068589.471 ft²
so
volume of water is
Vw = 7.2 × × 7068589.471 × 4.8
Vw = 244290.45
so water it yield is 244290.45 ft