All categories

3 years ago

If the sum of three consecutive numbers is 852, what is the middle one?

Mathematics

1 answer:

denis-greek [22]3 years ago

5 0

Divide the total by the quantity of numbers:

852/3 = 284

Because there are an odd quantity of numbers (3) the answer is the middle number.

The answer is 284

You might be interested in

If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

$C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11$

(b) Find the average cost at a production level of 1000 units.

$c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49$

$\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74$

(d) Find the production level that will minimize the average cost.

$c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100$

(e) What is the minimum average cost?

$c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220$

5 0

3 years ago

Jim is building a rectangular deck and wants the length to be 1 ft greater than the width. what will be the dimensions of the de

Travka [436]

Let x = width
x+1 is then the length

2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)

3 0

3 years ago

What is the mode of the data?

Luden [163]

Answer:

Step-by-step explanation:

Mode means most, so it's the number you see most.

5 0

3 years ago

Please help me please

Jlenok [28]

None of them because they are not in order

5 0

3 years ago

Tom has a large photo he wants to shrink to wallet-sized. It's width is 20 centimeters and it's len is 30 centimeters. If he wan

dsp73

We can use ratios, in other words, if one part of the photo is changed x times, how many times does the other part change?

We can set up the proportion as :
width 1 : length 1 = width 2 : length 2

20 : 30 = 5 : x

We do inverse multiplication, or multiply the outer with outer and inner with inner (W1 * L2 and L1 * W2)

20*x = 30*5
20x = 150
Divide all by 10
2x = 15
Divide all by 2 to isolate x
x = 15/2
x = 7.5cm

5 0

3 years ago