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Rudik [331]
2 years ago
15

Eight people, female and male, were surveyed about their choice of car color, green or blue. The table shows the choices they ma

de.
Which two-way table correctly compares the categorical data?

Person Gender
(male or female) Car color
(green or blue)
1 female green
2 female green
3 female blue
4 male blue
5 male green
6 female blue
7 male blue
8 male blue


A.
Green Blue
Female 4 5
Male 4 3

B.
Green Blue
Female 2 1
Male 2 3

C.
Green Blue
Female 4 4
Male 3 1

D.
Green Blue
Female 2 2
Male 1 3
Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0
Hello there.

<span>Eight people, female and male, were surveyed about their choice of car color, green or blue. The table shows the choices they made.

Which two-way table correctly compares the categorical data?
</span>
<span>B. 
Green Blue 
Female 2 1 
Male 2 3 </span>
Rom4ik [11]2 years ago
4 0
The <span>two-way table correctly compares the categorical data would be the second choice or letter B:

</span><span>Green Blue 
Female 2 1 
Male 2 3 
</span><span>
I hope my answer has come to your help. God bless and have a nice day ahead!

</span>
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I know the selected answer is correct but I'm not too sure how to get that answer.
Kryger [21]

\tt{ Hey \: there , \: Mr.Panda \: ! } ;)

♨\large{ \tt{ E \: X \: P \: L \: A \: N \: A \: T \: I\: O \: N}}:

⤻ Before solving the given question , you should know the answer of these questions :

✺How do you find the hypotenuse , perpendicular and base when the angle ( \theta \: , \alpha  \:  ,\beta ) is given ?

⇾ The longest side , which is the opposite side of right angle is the hypotenuse ( h ). There are two other sides , the opposite and the adjacent. The naming of these sides depends upon which angle is involved. The opposite is the side opposite the angle involved and it is called the perpendicular ( p ) . The adjacent us the side next to the angle involved ( buy not the hypotenuse ) and it is called the base ( b ).

☄ \large{ \tt{REMEMBER}} :

  • \bf{ \sin \theta =  \frac{opposite}{hypotenuse}  =  \frac{perpendicular}{hypotenuse}  }

  • \bf{ \cos\theta =  \frac{adjacent}{hypotenuse}  =  \frac{base}{hypotenuse}  }

  • \bf{ \tan \theta =  \frac{opposite}{adjacent}  =  \frac{perpendicular}{base}  }

In the above cases , \theta is taken as the angle of reference.

♪ Our Q/A part ends up here! Let's start solving the question :

❈ \large{ \tt{GIVEN}} :

  • Perpendicular ( p ) = ? , Hypotenuse ( h ) = 18 & base ( b ) = 16

✧ \large{ \tt{TO \: FIND} : }

  • Value of tan \theta

✎ \large{ \tt{SOLUTION}} :

Firstly , Finding the value of perpendicular ( p ) using Pythagoras theorem :

❃ \boxed{ \sf{ {h}^{2}  =  {p}^{2}  +  {b}^{2} }} [ Pythagoras theorem ]

\large{ ⇢ \sf{p}^{2}  +  {b}^{2}  =  {h}^{2} }

\large{⇢ \sf{ {p}^{2}  =  {h}^{2}  -  {b}^{2} }}

\large{ ⇢\sf{ {p}^{2}  =  {18}^{2}  -  {16}^{2} }}

\large{⇢ \sf{ {p}^{2}  = 324  - 256}}

\large{⇢ \sf{ {p}^{2}  = 68}}

\large{⇢ \sf{p =  \sqrt{68}}}

\large{ ⇢\sf{p =  \boxed{ \tt{2 \sqrt{17}}} }}

Okey, We found out the perpendicular i.e \tt{2 \sqrt{17}} . Now , We know :

❊ \large{ \sf{ \tan \theta} =  \frac{perpendicular}{base} }

\large {\tt{↬ \: tan \theta =  \frac{2 \sqrt{17} }{16}}}

\large{ \tt{ ↬ tan  \theta =  \frac{ \cancel{2} \:  \sqrt{17} }{ \cancel{16} \:  \: 8} }}

\large{ \tt{ ↬ \boxed{ \tt{tan \theta =  \frac{ \sqrt{17} }{8}}}}}

⟿ \boxed{ \boxed{ \tt{OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{ \frac{ \sqrt{17} }{8}}}}}}}

۵ Yay! We're done!

♕ \large\tt{RULE \: OF \:SUCCESS }:

  • Never lose hope & keep on working ! ✔

ツ Hope I helped!

☃ Have a wonderful day / evening! ☼

# StayInAndExplore ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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Answer:

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Step-by-step explanation:

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Factor common terms out of 45 x^3 y^2 + 5 x^2 y.

Factor 5 x^2 y out of 45 x^3 y^2 + 5 x^2 y:

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Answer:

undefined

Step-by-step explanation:

(-7, -7) and (-7, 1)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(1 - (-7)) / (-7 - (-7))

Simplify the parentheses.

= (1 + 7) / (-7 + 7)

Simplify the fraction.

8/0

= undefined

Our line is a vertical line, which has an undefined slope.

Hope this helps!

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