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slava [35]
3 years ago
12

If the diameter of a wheel is 0.5 meters, then the radius of the wheel is how many centimeters

Mathematics
2 answers:
NISA [10]3 years ago
8 0
Radius = diameter x 0.5
0.5x0.5 = 0.25meter

0.25 meter x 100 cm (100cm in one meter) = 25cm

also for future reference circumference = pie x r squared.
vladimir2022 [97]3 years ago
8 0
25 centimeters
The diameter of the circle is 0.5 meters which equals to 50 centimeter
Radius is half of a diameter so half of 50 centimeter is 25 centimeter
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A class is going on a field trip to see a movie. Each ticket is $8.00. The number of students, n, who will receive a $8.00 ticke
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The equation would be 8n=c

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6 0
3 years ago
The height in feet is modelled by the function below, where the t is in
Sedaia [141]

The object reaches the lowest height at 5 seconds

<h3>How to determine the time?</h3>

The function is given as:

f(t) = -2t² +22t + 6

Differentiate the function

f'(t) = -4t +22

Set to 0

-4t +22 = 0

Subtract 22 from both sides

-4t = -22

Divide both sides by -4

t = 5.5


Remove decimal points

t = 5

Hence, the object reaches the lowest height at 5 seconds

Read more about quadratic functions at:

brainly.com/question/1214333

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6 0
2 years ago
A cube has a volume of 1000 cubic feet. What us the edge length of the cube?
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7 0
2 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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