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ruslelena [56]
3 years ago
12

What expression is equivalent to 5 (x+6)-2x+9.

Mathematics
1 answer:
myrzilka [38]3 years ago
7 0
5x+30- 2x+9

3x+39 is the expression.
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Given f(x)= -2x+7 G(x)x/-2+7/2<br> Find g(f(x))
hodyreva [135]

Answer: g(f(x)) = g(x²-7)=x

Step-by-step explanation:

8 0
3 years ago
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3/8<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B8%7D%20%28x%20-%201%29%28x%20-%209%29" id="TexFormula1" title=" \fr
Verdich [7]
The first step for solving this expression is to distribute \frac{3}{8} through the first set of parenthesis.
( \frac{3}{8}x -  \frac{3}{8}) × (x - 9)
Now use the FOIL method to multiply each term in the first parenthesis by each term in the second parenthesis. This will look like the following:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x - \frac{3}{8} × (-9)
Remember that multiplying two negatives together equals a positive,, so the expression changes to:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x + \frac{3}{8} × 9
Calculate the product of all of the sets of multiplication to make the expression become:
\frac{3}{8}x² - \frac{27}{8}x - \frac{3}{8}x + \frac{27}{8}
Lastly,, calculate the difference of - \frac{27}{8}x - \frac{3}{8}x to find your final answer.
\frac{3}{8}x² - \frac{15}{4}x + \frac{27}{8}
Let me know if you have any further questions.
:)
8 0
3 years ago
(3x - 2)³= <br>gives the solution pls.​
Nonamiya [84]

Answer:

27x^3 - 54x^2 + 36x - 8

Step-by-step explanation:

(3x - 2)^3

= (3x - 2) (3x - 2) (3x - 2)

= 27x^3 - 54x^2 + 36x - 8

Hope this helps :)

Let me know if there are any mistakes!!

5 0
3 years ago
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You charge $2 per evening plus $5 per hour to babysit and you only charge for whole hours. You have a goal to earn at least $121
KATRIN_1 [288]

Answer:

8 hours

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Factorise 12u-uv please help lol
max2010maxim [7]

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

6 0
3 years ago
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