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satela [25.4K]
3 years ago
14

Find the area of the following polygons: Given: AC=12 PLS SEND HELPPPP

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

54 square units

Step-by-step explanation:

Assoli18 [71]3 years ago
6 0

Answer:

54 units²

Step-by-step explanation:

½×5×12 + ½×4×12

30 + 24

54

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What is the equation of the line that passes through the point (-4, 2) and has a<br> slope of ?
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Step-by-step explanation:

What is the slope please

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What is the equation of this line?
igor_vitrenko [27]

Answer:

Y=4

Step-by-step explanation:

The line is horizontal, which means that variable would be 4. The line starts at 4, which mean the equivalent of the variable is 4.

7 0
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Which functions are symmetric with respect to the y axis<br>​
Inessa05 [86]

Answer:

A, B, and D

Step-by-step explanation:

Only the functions that have x by itself between the absolute value signs (A, B, and D) are symmetric with respect to the y-axis .

Placing a constant outside the absolute value signs moves the function up or down the y-axis but retains the symmetry.

Adding a constant inside the absolute value signs (as in C and E) moves the axis of symmetry to the left or right of the y-axis.

In the diagram, both A and B are symmetric with respect to the y-axis, but C has been shifted three units to the left.

4 0
3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
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