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3 years ago

ABCD is a quadrilateral. Three of the angles of ABCD measure 100°, 87, and 106°, respectively. Find the measure of the

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

Answer:

Step-by-step explanation:

The angles in a quadrilateral add up to 360 degrees.

100 + 87 + 106= 293

360 - 293 = 67

Setler [38]3 years ago

6 0

The missing angle is 67°. (A)

EVERY quadrilateral has four inside angles that add up to 360°. It doesn't matter whether the quadrilateral is the size of a strep bacterium or the size of a galaxy. The inside angles always add up to 360°. It's a quadrilateral thing.

In this question, the first three angles add up to (100°+87°+106°) = 293°.

From there, it takes 67° more to get to 360°, so that's what the fourth angle has to be.

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Leena consumes 400 calories at breakfast and 350 calories at lunch. She consumes StartFraction 2 Over 3 EndFraction. of her dail

mr_godi [17]

Answer:

The first and second one

Step-by-step explanation:

Had the problem an it showed that those two were correct hope I help

6 0

3 years ago

Read 2 more answers

Let Y1 and Y2 be independent exponentially distributed random variables, each with mean 7. Find P(Y1 > Y2 | Y1 < 2Y2). (En

ArbitrLikvidat [17]

Y₁ and Y₂ are independent, so their joint density is

$f_{Y_1,Y_2}(y_1,y_2)=f_{Y_1}(y_1)f_{Y_2}(y_2)=\begin{cases}\frac1{49}e^{-\frac{y_1+y_2}7}&\text{for }y_1\ge0,y_2\ge0\\0&\text{otherwise}\end{cases}$

By definition of conditional probability,

P(Y₁ > Y₂ | Y₁ < 2 Y₂) = P((Y₁ > Y₂) and (Y₁ < 2 Y₂)) / P(Y₁ < 2 Y₂)

Use the joint density to compute the component probabilities:

• numerator:

$P((Y_1>Y_2)\text{ and }(Y_1$

$=\displaystyle\frac1{49}\int_0^\infty\int_{\frac{y_1}2}^{y_1}e^{-\frac{y_1+y_2}7}\,\mathrm dy_2\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\int_{-\frac{3y_1}{14}}^{-\frac{2y_1}7}e^u\,\mathrm du\,\mathrm dy_1$

$=\displaystyle-\frac17\int_0^\infty\left(e^{-\frac{2y_1}7} - e^{-\frac{3y_1}{14}}\right)\,\mathrm dy_1$

$=\displaystyle-\frac17\left(-\frac72e^{-\frac{2y_1}7} + \frac{14}3 e^{-\frac{3y_1}{14}}\right)\bigg|_0^\infty$

$=\displaystyle-\frac17\left(\frac72 - \frac{14}3\right)=\frac16$

• denominator:

$P(Y_1$

(I leave the details of the second integral to you)

Then you should end up with

P(Y₁ > Y₂ | Y₁ < 2 Y₂) = (1/6) / (2/3) = 1/4

5 0

3 years ago

Guys what the question to this i need it ASAP

adelina 88 [10]

Answer:(8+24) divided by (12 * 4)

Step-by-step explanation: 8 + 24 = 32 and 12 * 4 = 48. 32 divided by 48 is 2/3.

8 0

3 years ago

How many triangles can be constructed with side lengths of 9.6 cm, 11.6 cm, and 21.2 cm?

nignag [31]

Answer: A) 0 triangles

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Explanation:

Adding up the two smaller sides gets us 9.6+11.6 = 21.2, but this result is not larger than the third side of 21.2

For a triangle to be possible, we need to be able to add any two sides and have the sum be larger than the third remaining side. This is the triangle inequality theorem.

I recommend you cutting out slips of paper with these side lengths and trying it out yourself. You'll find that a triangle cannot be formed. The 9.6 cm and the 11.6 cm sides will combine to form a straight line that is 21.2 cm, but a triangle won't form.

As another example of a triangle that can't be formed is a triangle with sides of 3 cm, 5 cm, and 8 cm. The 3 and 5 cm sides add to 3+5 = 8 cm, but this does not exceed the third side. The best we can do is form a straight line but that's not a triangle.

In short, zero triangles can be formed with the given side lengths of 9.6 cm, 11.6 cm, and 21.2 cm

3 0

3 years ago

Please help me with this and thank you

Anarel [89]

I think it’s D sorry if you get this wrong I also have to do my work

7 0

3 years ago