Answer:
Step-by-step explanation:
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First step multiply your terms in your first expression just to the 1 in the second expression like so:
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Anything times 1 is that anything.
That is, .
Now we are going to take the top expression and multiply it to the -x in the second expression. . We are going to put this product right under our previous product.
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We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:
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Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us . (I'm going to put this product underneath our other 2 products):
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I'm going to again insert some zero placeholders to help me line up my like terms for the addition.
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----------------------------------------------------Adding the three products!
Answer:
42
Step-by-step explanation:
Answer:
500$
Step-by-step explanation:
<span>You have mentioned that two of the angles of ΔKSD are
∠K=16° and ∠D=34°. So that would mean that ∠S=130°,
because∠K+∠D+∠S=180°. That's because all the angles
of any triangle must total 180°.
But you also say that ∠T=51°. But since no angle of
ΔKSD can equal 51°, neither can any angle of ΔWAT
equal to 51°. Therefore ∠T=51° is impossible!</span>
3(x-2)+4(2x-3)
Use distributive property
3(x)-3(2)+4(2x)-4(3)
=3x-6+8x-12
Combining like term
3x+8x-6-12
=11x-18. As a result, 11x-18 is another expression that equivalent for 3(x-2)+4(2x-3). Hope it help!