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4 years ago

336 oz equals to ho manylbs

Mathematics

2 answers:

prohojiy [21]4 years ago

7 0

The answer is 21 because 1 lb is 16 so 336 divide by 16 equals 21 so 1 multiply 21 is 21

Ann [662]4 years ago

6 0

16 ounces is a pound and the answer is 21 pounds

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A community college bookstore has a fixed monthly operating cost of $16,495 for salaries, their building, and taxes. The books t

skad [1K]

Answer:

$143,370 per month

Step-by-step explanation:

16495 + 8.75(14500) = x

16495 + 126875 = x

143370 = x

Answer: $143,370 per month

Hopefully this is right

7 0

4 years ago

The coordinates of point T are (0,4). the midpoint of ST is (7,-5). find the coordinates of point S

Nonamiya [84]

The formula of a midpoint:

$M_{ST}\left(\dfrac{x_S+x_T}{2},\ \dfrac{y_S+y_T}{2}\right)$

We have:

$T(0,\ 4)\to x_T+0,\ y_T=4\\M(7,\ -5)\to x_M=7,\ y_M=-5$

Substitute:

$\dfrac{x_S+0}{2}=7\qquad|\cdot2\\\\x_S=14\\\\\dfrac{y_S+4}{2}=-5\qquad|\cdot2\\\\y_S+4=-10\qquad|-4\\\\y_S=-14$

<h3>Answer: S(14, -14).</h3>

7 0

4 years ago

The prices for a loaf of bread and a gallon of milk for two supermarkets are shown below. Sue needs to buy bread and milk for he

ale4655 [162]

Answer:

B. 3.19b + 4.59m = 137.24

3.49b + 4.39m = $140.04

Step-by-step explanation:

A B

Bread $3.19 $3.49

Milk $4.59 $4.39

Sue paid $137.24 in supermarket A

Sue paid $140.04 in supermarket B

Let

Price of bread A=$3.19

Price of bread B=$3.49

Price of milk A=$4.59

Price of milk B=$4.39

Quantity of Bread=b

Quantity of Milk=m

Pb=price of bread

Pm=price of milk

Qb=Quantity of bread

Qm=Quantity of milk

For each supermarket

Supermarket A Equation

PbQb + PmQm =$137.24

3.19b+ 4.59m = 137.24

Supermarket B Equation

PbQb + PmQm=$140.04

3.49b + 4.39m = $140.04

Combining both equations

3.19b + 4.59m = 137.24

3.49b + 4.39m = $140.04

5 0

3 years ago

What is pi as a fraction?

elixir [45]

Pi as a fraction is 22/7.

Hope this helped☺☺

5 0

3 years ago

Read 2 more answers

Find x,y,z : 4x^2+2y^2+2z^2-4xy-4xz+2yz-2y+6z+10=0

xenn [34]

I hope this helps.

Answer:-

∴x−3y−4z=0

Explanation:

First we rearrange the equation of the surface into the form f(x,y,z)=0

x2+2z2=y2

∴x2−y2+2z2=0

And so we have our function:

f(x,y,z)=x2−y2+2z2

In order to find the normal at any particular point in vector space we use the Del, or gradient operator:

∇f(x,y,z)=∂f∂xˆi+∂f∂yˆj+∂f∂zˆk

remember when partially differentiating that we differentiate wrt the variable in question whilst treating the other variables as constant. And so:

∇f=(∂∂x(x2−y2+2z2))ˆi+

(∂∂y(x2−y2+2z2))ˆj+

(∂∂z(x2−y2+2z2))ˆk

=2xˆi−2yˆj+4zˆk

So for the particular point (1,3,−2) the normal vector to the surface is given by:

∇f(1,3,−2)=2ˆi−6ˆj−8ˆk

So the tangent plane to the surface x2+2z2=y2 has this normal vector and it also passes though the point (1,3,−2). It will therefore have a vector equation of the form:

→r⋅→n=→a⋅→n

Where →r=⎛⎜⎝xyz⎞⎟⎠; →n=⎛⎜⎝2−6−8⎞⎟⎠, is the normal vector and a is any point in the plane

Hence, the tangent plane equation is:

⎛⎜⎝xyz⎞⎟⎠⋅⎛⎜⎝2−6−8⎞⎟⎠=⎛⎜⎝13−2⎞⎟⎠⋅⎛⎜⎝2−6−8⎞⎟⎠

∴(x)(2)+(y)(−6)+(z)(−2)=(1)(2)+(3)(−6)+(−2)(−8)

∴2x−6y−8z=2−18+16

∴2x−6y−8z=0

∴x−3y−4z=0

8 0

3 years ago