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3 years ago

13

Explain how to estimate 586-321 two different ways

1 answer:

Olenka [21]3 years ago

3 0

One way: estimate 586 to 600 and 321 to 300. Second way: estimate your answer

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Simplify -4(3-1)+2 <br><br>

nikdorinn [45]

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses.

-4(3 - 1) + 2

3 - 1 = 2

-4(2) + 2

We have no exponents so go on to multiplication

-4(2) + 2

-4 * 2 = -8

-8 + 2

No division so go to addition

-8 + 2

When adding a positive number with a negative number you will act as if you are subtracting the two numbers, then take the sign of the largest number (disregarding the signs). In this case the largest number is 8 and its sign is negative. Your answer will have a negative sign.

-6

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Please hurry and answer

Katarina [22]

Answer:

64

Step-by-step explanation:

It’s directly adjacent to the other angle.

4 0

2 years ago

The planning committee at school has 10 members. Exactly four of these members are teachers. A four-person subcommittee with at

Kipish [7]

Answer:

865

Step-by-step explanation: The set of possibilities are:

Subcommittee is of 4 people according to:

4 teachers 0 other member total possibilities 1

3 teachers 1 teachers C₄,₃ = 4 and other member 6 6*4 = 24

2 teachers 2 C₄,₂ = 4!/2! = 12 2 (om) and C₆,₂ = 6!/4! = 30

30*12 = 360

1 teacher 3 (om) 4 and C₆,₃ = 6!/3! = 120

120*4 = 480

Total ways of committee 1 + 24 + 360 + 480 = 865

4 0

3 years ago

a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be

ElenaW [278]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Let the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

$\rightarrow$ Now, clearly it is forming a triangle.

So, in triangle ABC,

$\rightarrow$ $\sf{Tan50° \:= \: \frac{BC}{AC}}$

$\rightarrow$ $\sf{1.19 \:= \: \frac{BC}{50}}$

$\rightarrow$ $\sf{1.19 ×50\:= \: BC}$

$\rightarrow$ $\sf{59.5m\:= \: BC}$

$\rightarrow$ Hence, BC = 59.5m

So, BD(total height of the tower) $\sf{ = \:BC+CD}$

$\sf{= \:59.5+1.65}$

$\sf{=\: 61.15m}$

Therefore, total height of the tower = $\sf\purple{ 61.15m.}$

________________________________

Hope it helps you:)

5 0

2 years ago

Read 2 more answers

Ulleksa [173]

Answer:

dont use this

Step-by-step explanation:

oinf+euiv=4

7 0

3 years ago