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Katyanochek1 [597]
3 years ago
14

Debra bought 7 boxes of chocolates. Each box cost $9.55. How much did she spend?

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

$66.85

Step-by-step explanation:

One box equals $9.55.

There are seven boxes, so multiply the $9.55 by 7 to get your answer:

7 × 9.55 = 66.85.

Debra spent $66.85 for all seven boxes of chocolates.

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Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi
Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

\dfrac{f(b)-f(a)}{b-a}

compute the quantity

\dfrac{f(3)-f(0)}{3}

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6

And so the average rate of change is

\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4

3 0
4 years ago
URGENT NEED HELP
Sergeeva-Olga [200]
5/50 or 1/10 in winning a prize.
8 0
3 years ago
Read 2 more answers
Which inequality matches the given situation if w represents weight in pounds:Baby tigers can be no larger than 4 pounds.
ozzi

Given:

w be the weight in pounds of a baby tigers.

To find:

The inequality if baby tigers can be no larger than 4 pounds.

Solution:

Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.

Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

w\leq 4

Therefore, the required inequality is w\leq 4.

4 0
3 years ago
An animal shelter has 9 puppies. If the puppies are 36% of the total dog and cat population, how many dogs and cats are in the a
Luda [366]

Answer:

Let total number of dog and cat population in animal shelter be x.

As per the statement:

An animal shelter has 9 puppies.

⇒ Total number of puppies = 9

It is also given that if the puppies are 36% of the total dog and cat population.

⇒ 9 = 36\% \text{of}{\text{total number of dogs and Cat}

or

9 = \frac{36}{100} \times x

By cross multiply we get;

900 = 36 x

Divide both sides by 36 we get;

25 = x

Therefore, total number of dogs and cat population in animal shelter are 25


5 0
3 years ago
Need some help with this question in the image<br><br>Cheers​
iren [92.7K]

Step-by-step explanation:

a) 24.7×52.3=1291.81

On rounding off to 3 significant digits we get

1290

b)

\sqrt{ {42}^{2} -  {28}^{2}  }

\sqrt{1764 -784 }  =  \sqrt{980}

=31.304951

On rounding off to 5 significant figures we get

=31.305

c)

\sqrt[3]{78}  = 4.27265

On rounding off to 2 significant figures we get

=4.3

Hence required answers

a)1290

b)31.305

c)4.3

I hope it helped you

5 0
2 years ago
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