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ch4aika [34]
2 years ago
8

sean needs to finish reading his book in four days. he reads 1/3 of the book on the first day, 1/4 of the book on the second day

, 1/5 of the book on the third day. if he has still 13 pages to finish on the fourth day, how many pages are there in the book
Mathematics
1 answer:
emmainna [20.7K]2 years ago
8 0

Answer:

60 pages

Step-by-step explanation:

Day 1 : 1/3 book

Day 2: 1/4 book

Day 3: 1/5 book

Day 4: 13 pages

Total days 1 through 3 = 1/3 + 1/4 + 1/5 = 20/60 + 15/60 + 12/60 = 47/60

Day 4 = 1 - 47/60 = 13/60

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Help me with this quick!
lara [203]

6g+10≤35

Hope that helps!!! :D

3 0
3 years ago
You are hiring a limousine. One company charges a $60 reservation fee plus another $15 per hour. A second company charges a $25
anzhelika [568]

Answer:

7 hours

Step-by-step explanation:

Step one:

given data

let the total charges be y and the number of hours be x

Company A charges

$60 reservation fee plus another $15 per hour.

so

y=60+15x----------1

Company B charges

$25 reservation fee plus another $20 per hour

y=25+20x------------2

Step two:

equate the 2 expressions above we have

60+15x=25+20x

collect like terms

60-25=20x-15x

35=5x

divide both sides by 5

x= 35/5

x= 7 hours

5 0
3 years ago
The sales tax rate is 10%. If Julie buys a picnic table priced at $793.60,how much tax will she pay?
Elis [28]

Answer:

she will pay 79.36 in taxes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I will give u brainliest
Gnesinka [82]

Answer:

It is 18

Step-by-step explanation:

A^2+31^2=36^2

After that you simplify then solve and you'll get 18

6 0
3 years ago
Read 2 more answers
Help please?
Alla [95]
\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}

\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k
6 0
3 years ago
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