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shtirl [24]
4 years ago
10

What is the value of y in the equation 2(4y − 1) = 6

Mathematics
1 answer:
cupoosta [38]4 years ago
5 0
The answer is 3 :)).
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HELP PLEASE!!!!!!!!
Taya2010 [7]

Hi There! I’m happy to help! Answer: $23.05

Step-by-step explanation:

First, since there is 3 shirts that cost $25.65, multiply them. Product is $76.95. Now, we subtract the $76.95 from the $100, making $23.05 her change. Hope this helps!

8 0
3 years ago
Read 2 more answers
48 is what percent of 75
Dahasolnce [82]

Answer:

36

Step-by-step explanation:

Hope this helps!

8 0
3 years ago
Find the value or measure. Assume all lines that appear to be tangent are tangent. X=
aev [14]

According to the secant-tangent theorem, we have the following expression:

(x+3)^2=10.8(19.2+10.8)

Now, we solve for <em>x</em>.

\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}

Then, we use the quadratic formula:

x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Where a = 1, b = 6, and c = -315.

\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
7 0
1 year ago
PLS help<br> solve for x: -6(2x-5) = 18
Mashutka [201]

Hey!


-6(2x-5) = 18


Switch it around and it becomes:


2x - 5 = 18 \div -6


First find 18 ÷ -6


18 \div -6 = -3

Positive ÷ negative OR negative ÷ positive is always negative.


That leaves you with:


2x - 5 = -3


Switch that around and it becomes:


-3 + 5 = 2x


Find -3 + 5


-3 + 5 = 2


That leaves you with:


2 = 2x


Divide both sides by 2 to leave <em>x</em> alone


\frac{2}{2} =  \frac{2x}{2}


\framebox{x = 1}

4 0
3 years ago
Which of the following rational expressions has the domain restrictions X = -6 and x = 1?
Tcecarenko [31]

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression

\frac{(x+2)(x-3)}{(x-1)(x+6)}

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).

So answer is,

\frac{(x+2)(x-3)}{(x-1)(x+6)}

Option B is correct.

7 0
1 year ago
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